Thực hiện phép tính:a)\(\frac{3}{4}\)x\(\frac{16}{9}\)-\(\frac{7}{5}\):\(\frac{-21}{20}\)b)\(2\frac{1}{3}\)-\(\frac{1}{3}\)x [\(\frac{-3}{2}\) (\(\frac{2}{3}\) 0,4x5) ]c) (20 \(9\frac{1}{4}\)):\(2\fra...

NB

Người bí ẩn

11 tháng 8 2017

Thực hiện phép tính:a)\(\frac{3}{4}\)x\(\frac{16}{9}\)-\(\frac{7}{5}\):\(\frac{-21}{20}\)b)\(2\frac{1}{3}\)-\(\frac{1}{3}\)x [\(\frac{-3}{2}\)+(\(\frac{2}{3}\)+0,4x5) ]c) (20+\(9\frac{1}{4}\)):\(2\frac{1}{4}\)d) (6-\(2\frac{4}{5}\)x\(3\frac{1}{8}\)-\(1\frac{3}{5}\):\(\frac{1}{4}\)GIÚP MIK VỚI AI NHANH MIK TICK LUÔN...

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#Toán lớp 1

2

HC

Hô Chi MInh

11 tháng 8 2017

mình ngại viết

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HC

Hô Chi MInh

11 tháng 8 2017

a) 3/4x16/9-7/5:(-21/20)

=4/3-(-4/3)

=8/3

b)=7/3-1/3x[-3/2+(2/3+2)]

=7/3-1/3x[-3/2+8/3]

=7/3-1/3x7/6

=7/3-7/18

=35/18

c)=(20+37/4):9/4

=117/4:9/4

=13

d)=6-14/5x25/8-8/5:1/4

=6-35/4-32/5

=-11/4-32/5

=-183/20

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M

Mèo_Hanna

18 tháng 10 2018

Bài 1: Thực hiện phép tính:a, \(3\frac{1}{2}-\frac{1}{2}.\left(-4,25-\frac{3}{4}\right)^2:\frac{5}{4}\)b, \(\frac{3}{7}.1\frac{1}{2}+\frac{3}{7}.0,5-\frac{3}{7}.9\)c, \(\frac{125^{2016}.8^{2017}}{50^{2017}.20^{2018}}\)d, \(\frac{4^{2002}.9^{1001}}{16^{1001}.3^{2003}}\)e, \(\sqrt{25-16}-\left|-3,7+0,7\right|\)Bài 2: Tìm xa, \(\frac{1}{3}x+\frac{4}{5}=3\frac{4}{5}\)b, \(\left|x+\frac{3}{4}\right|-2,25=1\frac{3}{4}\)c, \(\left(-x+\frac{2}{5}\right)^4=\frac{1}{16}\)d,...

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#Toán lớp 7

2

KS

kudo shinichi

18 tháng 10 2018

\(3\frac{1}{2}-\frac{1}{2}.\left(-4,25-\frac{3}{4}\right)^2:\frac{5}{4}\)

\(=\frac{7}{2}-\frac{1}{2}.\left(-4,25-0,75\right)^2:\frac{5}{4}\)

\(=\frac{7}{2}-\frac{1}{2}.\left(-5\right)^2:\frac{5}{4}\)

\(=\frac{7}{2}-\frac{1}{2}.5.\frac{4}{5}\)

\(=\frac{7}{2}-2\)

\(=\frac{7}{2}-\frac{4}{2}\)

\(=\frac{3}{2}\)

\(\frac{3}{7}.1\frac{1}{2}+\frac{3}{7}.0,5-\frac{3}{7}.9\)

\(=\frac{3}{7}.\left(\frac{3}{2}+\frac{1}{2}-9\right)\)

\(=\frac{3}{7}.\left(2-9\right)\)

\(=\frac{3}{7}.\left(-7\right)\)

\(=-3\)

\(\frac{125^{2016}.8^{2017}}{50^{2017}.20^{2018}}=\frac{\left(5^3\right)^{2016}.\left(2^3\right)^{2017}}{\left(5^2\right)^{2017}.2^{2017}.\left(2^2\right)^{2018}.5^{2018}}=\frac{\left(5^3\right)^{2016}.\left(2^3\right)^{2017}}{\left(5^3\right)^{2017}.\left(2^3\right)^{2017}.2.5}=\frac{1}{5^4.2}=\frac{1}{1250}\)( tính nhẩm, ko chắc đúng )

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YM

Yuki Min JinWon

18 tháng 10 2018

1

a) \(3\frac{1}{2}-\frac{1}{2}\cdot\left(-4,25-\frac{3}{4}\right)^2\) : \(\frac{5}{4}\)

= \(3\cdot25:\frac{5}{4}\)

= \(3\cdot\left(25:\frac{5}{4}\right)\)

=\(3\cdot20\)

=60

b)=\(\frac{3}{7}\cdot\left(1\frac{1}{2}+0,5-9\right)\)

=\(\frac{3}{7}\cdot\left(-7\right)\)

=\(-3\)

c) =

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DK

Đỗ Kiều Minh Ngọc

4 tháng 8 2021

B1: Thực hiện phép tính :a, \(11\frac{3}{4}-(6\frac{5}{6}-4\frac{1}{2})+1\frac{2}{3}\)b, \(2\frac{17}{20}-1\frac{11}{5}+6\frac{9}{20}:3\)c, \(4\frac{3}{7}:\left(\frac{7}{5}.4\frac{3}{7}\right)\)d, \(\left(3\frac{2}{9}.\frac{15}{23}.1\frac{7}{29}\right):\frac{5}{23}\)B2: Thực hiện phép...

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#Toán lớp 6

0

DT

Đỗ Thị Minh Anh

8 tháng 4 2019

Bài 1: Thực hiện phép tính bằng cách hợp lí ( nếu có thể ) a, \(-\frac{4}{5}-\frac{8}{25}\left(\frac{-5}{2}-0,125\right)\) c, \(5\frac{1}{2}-4\frac{2}{3}:\frac{16}{9}-3\frac{1}{3}:\frac{16}{9}\) Bài 2: Tìm x, biết a, \(\left(20\%x+\frac{2}{5}x-2\right):\frac{1}{3}=-2013\) b, \(\left(4,5-2\left|x\right|\right).1\frac{4}{7}=\frac{11}{14}\) HELP...

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#Toán lớp 6

1

👁💧👄💧👁

8 tháng 4 2019

Bài 1:

a) \(-\frac{4}{5}-\frac{8}{25}\left(\frac{-5}{2}-0,125\right)\\ =-\frac{4}{5}-\frac{8}{25}\left(\frac{-5}{2}-\frac{1}{8}\right)\\ =-\frac{4}{5}-\frac{8}{25}\left(\frac{-20}{8}-\frac{1}{8}\right)\\ =-\frac{4}{5}-\frac{8}{25}\cdot\frac{-21}{8}\\ =-\frac{4}{5}-\frac{-21}{25}\\ =\frac{-4}{5}+\frac{21}{25}\\ =\frac{-20}{25}+\frac{21}{25}=\frac{1}{25}\)

c) \(5\frac{1}{2}-4\frac{2}{3}:\frac{16}{9}-3\frac{1}{3}:\frac{16}{9}\\ =5\frac{1}{2}-\left(4\frac{2}{3}:\frac{16}{9}+3\frac{1}{3}:\frac{16}{9}\right)\\ =5\frac{1}{2}-\left(4\frac{2}{3}+3\frac{1}{3}\right):\frac{16}{9}\\ =5\frac{1}{2}-8\cdot\frac{9}{16}\\ =\frac{11}{2}-\frac{9}{2}=\frac{2}{2}=1\)

Bài 2:

a) \(\left(20\%x+\frac{2}{5}x-2\right):\frac{1}{3}=-2013\\ \left(\frac{1}{5}x+\frac{2}{5}x-2\right)\cdot3=-2013\\ \left[x\left(\frac{1}{5}+\frac{2}{5}\right)-2\right]=\left(-2013\right):3\\ x\cdot\frac{3}{5}-2=-671\\ x\cdot\frac{3}{5}=-671+2\\ x\cdot\frac{3}{5}=-669\\ x=\left(-669\right):\frac{3}{5}\\ x=\left(-669\right)\cdot\frac{5}{3}\\ x=-1115\)Vậy x = -1115

b) \(\left(4,5-2\left|x\right|\right)\cdot1\frac{4}{7}=\frac{11}{14}\\ \left(\frac{9}{2}-2\left|x\right|\right)\cdot\frac{11}{7}=\frac{11}{14}\\ \frac{9}{2}-2\left|x\right|=\frac{11}{14}:\frac{11}{7}\\ \frac{9}{2}-2\left|x\right|=\frac{11}{14}\cdot\frac{7}{11}\\ \frac{9}{2}-2\left|x\right|=\frac{1}{2}\\ 2\left|x\right|=\frac{9}{2}-\frac{1}{2}\\ 2\left|x\right|=4\\ \left|x\right|=4:2\\ \left|x\right|=2\\ \Rightarrow\left[{}\begin{matrix}x=2\\x=-2\end{matrix}\right.\)Vậy x ∈ {2 ; -2}

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PN

Phạm Ninh Đan

1 tháng 8 2020

\(a,\left(9,75.21\frac{3}{7}+\frac{39}{4}.18\frac{4}{7}\right).\frac{15}{78}\) \(b,\frac{-7}{21}+\left(1+\frac{1}{3}\right)\) \(c,\frac{2}{15}+\left(\frac{5}{9}+\frac{-6}{9}\right)\) \(d,\left(\frac{-1}{5}+\frac{3}{12}\right)+\frac{-3}{4}\)...

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#Toán lớp 6

0